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18x^2+35x-2=0
a = 18; b = 35; c = -2;
Δ = b2-4ac
Δ = 352-4·18·(-2)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-37}{2*18}=\frac{-72}{36} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+37}{2*18}=\frac{2}{36} =1/18 $
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